A 4-volt drop with a small motor on a car battery is rather "shocking".

wire became comparable with the resistance of the motor and therefore i had created a voltage divider circuit. Am i correct on this?

**EXACTLY!** If you have a small battery that can't put-out the required current, so that the voltage drops when you apply a load, we attrbute this to the

*internal resistance* of the battery (or power supply).

Just to clarify something -

**Ohm's Law ALWAYS HOLDS!** But, it can get tricky with non-linear devices and loads (motors, semiconductors, LEDs, etc.) because

**the resistance/impedance changes under various conditions.** When you put a heavy load on a motor, the impedance drops and you get more current. The Ohm's Law relationship between current, voltage and impedance is still true... If voltage is held constant and current increases when you put a load on the motor, impedance

**must** have decreased.

Another time Ohm's Law can get confusing is with capacitors and inductors in AC circuits, where current and voltage are out-of-phase. If you use a multi-meter to measure voltage and current, you might

*think* Ohm's Law is wrong (because you are measuring the average or RMS voltage and current). But, at any

*instant* in time, Ohm's Law holds.