johnwasser:
It's the formula I showed earlier. The resolution of the FFT is sampleRate/sampleCount. To get resolution of 0.0001 Hz (1/10,000th Hz) you need sampleCount to be 10,000 times the sampleRate.If each sample is a 2-byte integer you need 2*sampleCount bytes to store them.
Got it! 2100009259/(2^20) = 176 mB.
Thank you so much!