For a project I needed both / 10 and %10 several times. Although the straightforward code was fast enough I investigated if it could be even faster. Could be useful e.g. for a library or so. This resulted in the following divmod10() function that calculates both the divide by 10 and the modulo 10 "s…

divmod10() : a fast replacement for /10 and %10 (unsigned)

Coding_Badly May 21, 2013, 1:36am 3

No timing comparison to the div / ldiv functions?

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