Hi there, i have a simpile question abpur angulare velocity.
i want to know if a quadcopter fly with angle 15 degrees. the angulare motion change or equal to 0 ??.
logicaly it equal to 0.
but me i have a problem to progrmming my quadcopter.
i want to contol il with angulare rate. but the problem i can't change the orionation of the quadcopter if the stick in the center. i should send negative value to turn it in the right. and positve value for theleft orientation.
i saw video on youtube that when the stick =0, the quadcopter stop turning !!!! ??? i don't understand why.
logicaly it keep his last moove.
let's we say my input = 50°/s and my sensor is 0°/s so the controler = -50/s so this value will sent to the motor for spining. so when the motor in his max spining the angulare rate =0. because there is no motion. so even we send positive 1 12 40 50 the quadcopter will not moove , iyt keep the max orientation. so i should send negative value to spin because the new commande will be -50°/s sensor =0 se the output will be -50 and it will spin the quadcopter to the max left.
me i attache the drone he is not flying. so i want to know if the drone fly with 15 ° is the angulare rate =0 or not
Thanks for the replay.i'm sorry that i didn"t give details.
my problem is i don't understand how we can change the oriontation of the quadcopter only using angulare rate.
for me it is not logical. i will tell why.
imagine you have a control loop . 2 inputes, first input is the sensor of an angulare rate and senconde input is the desirede angulare rate. the outputs is a value that send to the motors. ok
so if i my sensor give me 0°/s and me i want to send 130°/s so the outpute is -130 and this value will rich the motors forwad motor will be more than the backword motors. ok
now imagine the quadcopter is in his full right. in that moment the angulare rate = 0 because there is no motion.
from the minute 32.23 to 33.42. when he send the 0°/S the quadcopter will not keep hid full left. he will rich the 0°/s !!!!???? but before when he was at full left his angulare rate is 0, so how do you explaine that the quadcopter will not keep his full left when you send him 0°/S
I think he means he doesn't want to try in French where he might be able to effectively communicate with someone and solve his problem but would rather keep posting incoherent nonsense here and never get it working.
I think he means he doesn't want to try in French where he might be able to effectively communicate with someone and solve his problem but would rather keep posting incoherent nonsense here and never get it working.
jone31 has been working on understanding "angular rate" for a few weeks now. At this rate he/she might have a properly functioning quadcopter in perhaps a decade, two decades tops.
Is there any way to change the orientation of a quadcopter? Only way I can think of is a tricky aerial manoeuvre where you lift one side, lift a side next to that one, then drop the copter back down to horizontal.
PaulMurrayCbr:
Is there any way to change the orientation of a quadcopter? Only way I can think of is a tricky aerial manoeuvre where you lift one side, lift a side next to that one, then drop the copter back down to horizontal.
I thought they used gyroscopic precession, biasing the speed of the clockwise and anticlockwise motors.
AWOL:
I thought they used gyroscopic precession, biasing the speed of the clockwise and anticlockwise motors.
That's nothing to do with precession, that's just applying a net torque by balancing the torques
from the two sets of props that counter-spin.
Back to the original question - you are asking why a particular quadcopter's control software is
programmed as it is - that is a question for the author of that software, not for the Arduino
forum.