Go Down

Topic: Is this circuit correct? (Read 59 times) previous topic - next topic


Just need to know if this circuit is correct. Making a 4 bulb lamp and needed to wire everything in parallel.


what's up with lamp3 and 4 having 0 ohms of resistance ?
Expert To Be: Machine Learning And Computer/Machine Vision (ML/CV/MV)


The zero-ohms makes no sense, but this is how lights are wired in parallel.

I can't tell from your drawing what is the power source.  120VDC ??
If the lamps are truly zero ohms, expect lots of smoke.


Lamps are loads and each load has some kind of Impedance= Resistive + Inductive. In your case, the lamps are resistive loads (with a really small value of resistance) that dissipate energy (this energy converted into heat and light). The zero ohm resistance indicates a short circuit between the positive and negative side and this will leed into a smoky situation.  8)

So if you want to simulate your circuit in terms of power dissipation, current consumption, voltage drop, etc you need to take into account this resistance.

I am not sure what the PWL and CSV stand for but as SteveMan pointed, 120VDC it's a kind of strange. May you need to replace your power source with an AC one?

The parallelization is correct


OPs circuit;

If they are all 120V bulbs then this config will be okay.
Some incandescent bulbs measure near zero ohms when measured with a multi-meter and COLD.
Their resistance increases as they heat up and glow, hence you usually have  HIGH instantaneous switch on current.

Tom... :)
Everything runs on smoke, let the smoke out, it stops running....


what's up with lamp3 and 4 having 0 ohms of resistance ?
Sorry that was just a mistake in the drawing. Disregard the 0 ohms. Also the power source is 120v AC

Go Up