Ok, I rewired my board but didn't see any change:

` D00 D01 R0`

+-(A)------+-|>|--|>|--'\/\,--+

| | D10 D11 R1 |

E=5v _|_ +-|>|--|>|--'\/\,--+

I=100mA _-_ | D20 D21 R2 |

-200mA - +-|>|--|>|--'\/\,--+

| |

+--E\ /C----------------------+

|B

| RB

+---'\/,-- pin 12

RB = 330 ohms

Transistor = P2N2222A

Here are my calculations:

`E = 4.5V - 2.5V = 2.0V (each IR LED is about 1.25V)`

I = 100mA

R = 2.0V/0.1A = 20

1/R = 3/RR0

20 = RR0/3

RR0 = 20*3

= 60

So I happen to have 330 Ohm resistors on hand so, I could put 5 in parallel to get 66 Ohms or 6 in parallel to get 55 Ohms. I used 5 in parallel.

Going backwards through the equations I just used, I can calculate current (I).

`RR0 = 66`

R = 66/3

= 22

I = E/R

= 2.0V / 22

= 90.9mA

Ok, so those are my calculations. Here is what I actually measured:

`V=4.46V`

I=48.9mA

VD0 = VD00 + VD01 = 2.55V

VD1 = 2.55V

VD2 = 2.54V

R0 = 66.0

R1 = 66.0

R2 = 65.5

To measure current and voltage, I moved base wire from pin 12 to +5V.

Current was measured at (A) in diagram, diode voltages were measured along lit diodes and resistances were measured while circuit was broken.

Could someone tell me what I'm missing in my calculations? This is driving me nuts.

Thanks