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### Topic: Converting TEMT6000 value to lux (Read 12136 times)previous topic - next topic

#### cklim85

##### Aug 29, 2013, 07:25 am
My apology as I'm a newbie in arduino.

output of TEMT6000 into lux?

I followed the code in bildr.org guide
http://bildr.org/2011/06/temt6000_arduino/

and the output value is from 0 - 1023.

I would like to convert the readings to LUX. How do I do it?

#### johnwasser

#1
##### Aug 29, 2013, 01:58 pm
In the datasheet you will find a chart that shows the relationship between lux and collector current.  From that chart you can calculate the formula.  Then you just need to convert the voltage measured to a current measurement.

The series resistor is 10,000 Ohms so the current should be voltage / 10000.

The voltage is: analogRead() * 5.0 / 1024.0
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#### cklim85

#2
##### Aug 30, 2013, 07:03 pm

In the datasheet you will find a chart that shows the relationship between lux and collector current.  From that chart you can calculate the formula.  Then you just need to convert the voltage measured to a current measurement.

The series resistor is 10,000 Ohms so the current should be voltage / 10000.

The voltage is: analogRead() * 5.0 / 1024.0

Thank you for your advice. Based on the chart I find out that the formula is y = 1/2(x) + 0. Please correct me if I'm wrong.

#### johnwasser

#3
##### Aug 31, 2013, 01:32 am

Thank you for your advice. Based on the chart I find out that the formula is y = 1/2(x) + 0. Please correct me if I'm wrong.

I agree.  So lux = 2 * microamps.

Code: [Select]
`float volts = analogRead() * 5.0 / 1024.0;float amps = volts / 10000.0;  // across 10,000 Ohmsfloat microamps = amps * 1000000;float lux = microamps * 2.0;`

Or to mash it all together:
Code: [Select]
`float lux = analogRead() * 0.9765625;  // 1000/1024`

This should give you a value between 0 and 1000 lux.
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#4

#### bitNine

#5
##### Oct 05, 2015, 05:12 am
Just found this thread while trying to figure out how to calculate lux with a cheap light meter I bought. NO data sheet available. I've checked the resistance of the photoresistor, and it's 20k ohms when dark, and close to 200 ohms with a bright flashlight. Attempting to use the code above, it seems that one flaw is that the voltage is backwards. The lux value goes down when light is added, and up when light is taken away. Swapping it so that it's the difference from 5 volts of the volts value (volts = 5.0 - volts), gets pretty close, but it's still not right. I have a cheap lux meter that I used to try to calculate a lux:ohms table. It's crazy how NOT linear the photoresistor is. While darkness is 20k ohms, 41 lux is ~6k ohms. 14k ohms for 40lux is certainly not linear to the max of 155 ohms at 110,000 lux.

The question is, might this just have to do with this specific photoresistor, or is it common for them to not have linear values like that? I have a TEMT6000 on order, and really want to be able to calculate lux values. Maybe my cheap lux meter is, um... cheap.

#### bitNine

#6
##### Oct 08, 2015, 09:03 am
For the record, I got the TEMT6000, and while it works, it FREAKS out with any light that is over 1000 lux. The calculation here works relatively well. Definitely different from the other light sensor I tested.

#### rrwiyatn

#7
##### Mar 31, 2016, 11:45 pm
Hi guys,

if I change the resistor to 1K instead 10K, can I measure up to 10k lux? If yes, what will be the formula to calcualte the lux?

I already changed the resistor and it seems that it can go higher than 1K lux. I just don't know where the saturation point is..

Also, isn't this sensor use log scale?

Rey

#### bryan_brennan

#8
##### Nov 15, 2019, 09:18 pm
I performed the conversion mentioned above, but my TEMT6000 reads only ~25% the lux read by my lux meter.

Can you think of a reason for this discrepancy?

Also, is the 10k Ohm resistor something that you added to the circuit? Or is it something internal to the TEMT6000 board?

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