you get this page : blue led and you'll see that there is already an internal resistor, thus it needs to be powered at 12V (not 5V)
If the led is designed for 12V, you'll have to use a transistor or a FET (included in the kit) to drive it from Arduino.
Well no, it doesn't.If you do look at the datasheet, you will see that it is specified for a minimum of 4V, so it just does not shine quite as bright at 5V as it does at 12.
it was late here and I didn't look at the curves. I .... needed to sleep, I guess
You need to know 3 things - the rated current for the LED, I, the forward voltage, Vf, and yoursupply voltage, VsR = (Vs - Vf) / I
What is the energy unit called that is responsible for flipping a relay? Power, current, amps?
My guess is that you didn't "blow" any leds
All of your questions are the result of not understanding Ohm' Law. Learn it.
And BTW,The word is "ENERGIZE" not "FLIP". At least make an effort to learn the proper nomenclature forthe technology you are "trying" to learn.
AGAIN, read the datasheet for the relay.
So if i understand correctly (which I'm really iffy of) the resistor I purchase needs to be able to "ENERGIZE" using .0409 Amps.
FYI,If you really do have a led with a forward voltage of 14 V like this one then you need to finda power supply that supplies 16 to 24V and use a current limiting resistor in series with the led. It says theforward current is (Typically) 7.5 mA, so for example :
Also, be careful when comparing LED mcd ratings. mcd depends not only on brightness, but how widely or narrowly the light is focused (review definition of mcd, vs the lumen).
To have the relay work in series with the LEDs is a rearly bad idea. It requires that you know a lot more about your components that you do. I am not sure it is even possible because relay tripping voltages and currents are often totally different from LED ones.
Don,t put them in series You CAN use a relay to turn on the led or put them in parallel with independentcurrent limiting resistors.