Next up any half way good cable installer knows that you don't run data cable with the power wires.
Which is of coruse correct for safety and interference reasons.
However this bodes against using the power ground as the reference for both ends of the data link as by separating the two, you have clearly
created a loop.
Then there this ground is at ground if one wire and grounded when you loop it it becomes a coil so like a coil
each tap can have a higher then ground level. That's why you use star grounds. And in this case one long ground with no loops
But it is not the
closure of the loop that creates a ground loop - it is the
structure of the loop. A loop is caused by a "return" being separate from the active (or in this case, actives).
Ground loop current is limited by inserting an 100Ω resistor in inline with the RS485 ground.
Which indeed limits the
current, but not the voltage, so it is of no use in removing a ground voltage mismatch. It is in fact useless; just a half-hearted version of simply disconnecting the ground entirely or more accurately, providing some sort of second-rate ground if the
other part of the loop is broken.
I highly recommend to also read this.
- Unconnected ground topology works as long as the potential difference between grounds is kept to a minimum (less than a few volts)
Less than one volt according to the specifications I previosuly cited.
- Ground connection topology works better but then again if there is significant potential difference between grounds you risk a ground loop current. In this case opto-isolation is required.
The current is not the point other than in terms of safety. It is the
voltage that matters. Because the data ground will be the part of the cabling "loop" with the highest resistance, the voltage will still apaear between its ends, only marginally less thn if they were not conencted in the first place.
However MIDI uses a shield which is connected at one end only and thus does not take part in the question about being a reference voltage.
No, it does not take part in the question about being a reference voltage because the data path
is opto-isolated and requres no reference voltage. The shield ground is irrelevant.