If that's a current limiting resistor, then the value should be chosen to drop the difference after subtracting 1.4V +1.4V + V
DSFET .
If we assume:
V
DSFET = 1.0 V,
Battery 1 = 1.4 V (charged)
Battery 2 = 1.4 V (charged)
Then the battery needs to drop 12V -1.4V-1.4V-1.00V = 8.2V
If we assume a Charging current = 300 mA ,
Then R
CL = 12.0v/0.300 A = 27.3 ohms
P
R = 0.300A * 8.2V = 2.46 W (round up to 3W)
R
CL =
27 ohm/3Whe current through the battery forms a voltage through that resistor. The voltage is then fed back into that op amp.
Yes, thats not feedback though, the comparator operates in open loop mode.
Thats the input voltage and the V
ref for the
comparator is the +V pin.
If +V > -V, Vout = +Vcc
+V < -V, Vout = 0V
Vref = 8.2 V (in above example)
The "feedback " line , as you call it is connected to the wrong pin on the comparator.
The operation should be :
( 0.30 A * 27 ohms = 8.2 V)
If I
charging < 0.3A +V < 8.2V
If I
charging > 0.3A +V > 8.2V
If I
charging < 0.300 A (-V < 8.2 V)
Vout = +Vcc (fet ON)
If I
charging > 0.300 A (-V > 8.2 V)
Vout = 0 V (fet OFF)