You can wire three "protected" cells in series by yourself!
What we are saying is to buy three individual, protected 3.7V cells and wire them in series, one after the other, negative of one cell to positive of another. This will create a (nominal) 11.1 V battery pack. Like this:You do not need to add another protection circuit.
A theoretical discussion only. The battery protection circuits usually cut out at 2.8 V or less. The one pointed to by the OP has this cutout:
urnigy has 4 wires (red, blue , yellow, black), used when I recharge the battery. Are the coloured wires the 1's , 2's and 3'd positive terminals, as requested by the connection instruction?Is the black wire the 3's cell negative terminal?
Use the same charger you are now using for your 11.1V (3 S) pack.
Obviously you don't use the batteries and believe whatever you read.
This is the charger I'm using:http://www.himotoracing.com/product/electronic/electronic_027/images/electronic_027_01.jpg
Thanks a lot Jremington! This is exactly the schema and data about voltages I was looking for.
my current charger reports "Max Charge current: 3x900mA", I guess this is too much
However, even with this protection it is very important that you only use a LiIon/LiPoly constant-voltage/constant-current charger to recharge them and at a rate of 500mA or less. Like most lipos, the batteries we sell do not have thermistors built in. This is why we suggest charging at 1/2C or even less - 500mA max in this case which is how much you can get from a USB port.
Did you try taking the voltage measurements just to see for yourself how it corresponds to the illustration jremington posted ? (just for curiosity) After doing so, does it make sense that the schematic is really unnecessary if you can read the voltages ? Which would you think would be more reliable, the schematic or the actual voltages ?