This Step down module for example has an max output of 3A, with cooling. Now, am I going to reach that level of current?
The battery is connected to a petrol engine and charged with an alternator, so the voltage will reach to about 14.4 volts. note that we are not talking about a car, but some sort of buggy/monopost. it will not have additional electronic system such as cigarette lighter port, or ECU. it is a carburetor engine.
So you are saying it is possible to perform multiple task at the same time, such as reading 2 sensors, driving 2 stepper motors and displaying information on the lcd's in real time? As in the same second?
The tread was actually continued here, because i asked a question on javbus's thread and it continued like that until somebody asked me to create a new post.
Find out how much current each device uses [the maximum [ever] amount it is likely to use], then add it all up. If it's less than the rated amount the supply can deliver, then you're good -- but, consider that often a max current rating on a supply is the amount of current it will handle in the most "stressful" way -- i.e. that usually means heat dissipation. So, rule of thumb, use a supply rated at 150% to 200% of the actual load.
So, you can't hurt it by trying to draw more current from it than it can consistently deliver,
. note that we are not talking about a car, but some sort of buggy/monopost.
I have a number of Unos with blown regulators on my shelf that disagree.
As in the same millisecond. The Arduino can do 16000 things in a millisecond. (Thousandth of a second.)
Note that each relay will be activated in an while loop,... <snip> ...and while the loop is activated, about 3-4 seconds, the board cannot do another task, such as reading values from different senzor and output the data on lcd's, led's and so on.
( i know there is another way to write the program, i read about it,...)