working of Inverter

[tjones9163]

Hello, I am once again trying to wrap my head around inverters.

Let's say I have an appliance that uses 1000 watts and its maximum current is 10amps.
I also have a 2000w inverter and a 12v battery.
Is the math correct to say 1000w/12v = 83.3A

My question is,
Is it the battery that must be able to output 83.3 amps to the inverter, and it is the inverter job to put out a regulated 110v at 10amps(required by my appliance), so it is not my appliance that needs to handle the 83 amps, but instead my battery to the inverter?

I'm pretty sure this is correct but I just wanted to make sure.
P.S I realize that I didn't include the type of battery or amp-hours, more of just a broad understanding.
Thanks

[ReverseEMF]

Yup!  That's correct! 

[tjones9163]

Yup!  That's correct! 

Awesome. Thanks

[ReverseEMF]

And, to elaborate: The battery current will be even a bit more, because the efficiency will never be 100%. 

Power out = Efficiency * Power In

So:
Pout = Eout * Iout
and
Pin = Iin * Ein
and e = % Efficiency
Pout = e/100 * Pin
Pout = e/100 * Ein * Iin
Iin = (100 * Pout) / (e * Ein)

so, assume an efficiency of 85%

Iin = (100 * 1000) / (85 * 12) = 98Amps!

[MarkT]

and it is the inverter job to put out a regulated 110v at 10amps(required by my appliance)

The inverter puts out a regulated 110Vac.  The load takes the current it needs, the inverter has no say
in this other than when overloaded.

The inverter is a voltage source.  If you control voltage, you cannot also control current.