But the EmonLib isn't really compatible with my TT 100-SD and the datasheet for my ct sensor isn't rich.
When I actually tried, all the results i've got where off the charts...
EO=IP∗RBTR where EO is the output voltage, IP is the current that will produce the voltage you want, TR is the transformer's turns-ratio, and RB is the burden resistance, in ohms.
Yes, and using the 1.1V internal AREF would yield an ADC result of about 1012.
Wouldn't the voltage across the burden resistor be 0.033A * 33 Ohms (1.089V) rms for IIN = 100A ?
Yes, which is ~3volt peak/peak for the 5volt pin, or 3/5 of the range of the A/D.Working backwards gives you a burden resistor of about 53ohms for 100A>5volt peak/peak.
No, this is AC, not DC.Yes, which is ~3volt peak/peak for the 5volt pin, or 3/5 of the range of the A/D.Working backwards gives you a burden resistor of about 53ohms for 100A>5volt peak/peak.Leo..
So following this, and your responses, instead of ""current constant = (100 ÷ 0.050) ÷ 18 = 111.11"" 111.11I should use : current constant = (100 ÷ 0.050) ÷ 53.5 = 37,383 // 51 = 39,215 ?
current constant = (100 ÷ 0.050) ÷ 53.5 = 37,383 // 51 = 39,215 ?
current constant = (primary current ÷ secondary current) ÷ burden = xcurrent constant = (100 ÷ 0.033) ÷ 51 = 59,41759,417 being the calibration in my code with the Emonlib library
According to Integrated Publishing: Electrical Engineering Training Series, you would use the following formula to determine average current: I avg = 0.636 X I max. I avg is the average current from zero to peak and back to zero (one alteration) I max is the "peak" current. (The unit of measurement for current is the ampere or amp.)Let Irms = 100AThen IPeak = (SQRT(2) * IRMS = 1.41421 * 100 = 141.421 AI avg = 0.636 X I max. = 0.636 *141.421 A. = 89.94 ASo unless you can link the page from that website that contains the formula you posted, whichis it ?A. constant current (ie constant current circuit)B. current constant (ie a software constant "const" reprepresenting current)C. AVERAGE current (as explained above but self explanatory) Write, on a piece of paper, the formula for finding average current: I avg = 0.636 X I max.
Isecondary = CTturnsRatio × IprimaryCTturnsRatio = Turnsprimary / Turnssecondary