Well given a BJT needs about 5 to 10% of the output current to the base, you'll need another
transistor to drive a 2SC5242 (C5242 is the marking, the device code is 2SC....)
Much easier to use a logic-level MOSFET surely?
And as the 2SC5242 is designed for linear operation its switching performance is probably awful (long
turn off delay from saturation).
Having said that its a transistor, it has gain, drive it properly and don't exceed its maximum
ratings and it will work.