12V Electric Lock issue

Other Hardware Motors, Mechanics, Power and CNC
1

Hi, my system is connected like that:

Screenshot 2023-09-04 173728
Screenshot 2023-09-04 173728776×314 65.6 KB

In words, I have a 18650 3.7V lithium ion battery(3500mAh, 12.85Wh) connected to a 12V boost(up to 2A), an RF module that when receives a signal outputs the input voltage(QAChip 433Mhz module also up to 2A), and finally an electric lock(XM-11) - consume 0.8A-1.2A.
When using everything without the lock it works fine, using the lock makes the battery goes around 1V and stops the system from working.
Using a power supply works fine, but I want it to be 3.7V battery operated, what is the issue and what can I do to solve it?

2

What's the status when you set the power supply to "3.7V" (battery equiv.) ?

3

When powering 3.7V from a power supply, the lock works when I send the signal to the module, and stops when I stop.
I can see that its below 1A.

4

Why not answer my question?

5

I thought I did, could you clarify it?

6

Buena suerte y Adiós.

7

The boost converter will draw around 4 Amperes when the lock draws 1.2A. If the battery has an overload protection circuit, it may be triggered.

8

Thanks, does it make sense that it is that low(4A)? Is there something I can do in such a case to remain with this battery?

10

What do the specifications for the battery say?

Is it designed for such a high current - that's greater than 1C discharge rate.

11

Your schematic shows a CR1220 not a 18650

12

I'm using a 18650 3.7V lithium ion battery(3500mAh), protected by a PCM module, unfortunately that's all I know.

13

Was it a known brand, or just some cheap no-name?

14

I bought at it at a store, not aliexpress

WhatsApp Image 2023-09-04 at 18.09.39
WhatsApp Image 2023-09-04 at 18.09.391536×2048 219 KB

Sorry, the schematic is misleading, just used a battery drawing didn't notice the writing.

15

Your schematic shows other things connected to the battery. What are they?

16

Is the battery fully charged?

17

What is "its" in that sentence in your post #3?

18

On the left is a charging module connected directly to the battery, it is 3.7 now, not fully charged.

19

The current written on the voltage supplier, but I will recheck it.

20

I don't understand the question. The boost converter will draw current Iin greater than about 1.1*Iout*Vout/Vin.

That is, if the boost converter can handle that much input current.

21

Go back and ask the store if it's good for delivering 4A?

You could just test it - set up a 4A load, apply it to the battery, and see what happens...