18B20 Temerature Sensor , 0.5c reading

Projects Programming
1

I have one problem ... I use 18b20 sensors its works ok ,but his sensitivity is 0,01 ...he show me 15,56 ... 15.87 ...but I need something like 15,5 ... 16,0 .... just 0,5 diference how to do that ....

part of my code

#include <DallasTemperature.h>
#include <OneWire.h>

OneWire oneWire(9); //pin 9
DallasTemperature sensors(& oneWire);

sensors.requestTemperatures();
float Senzor1;
Senzor1 = sensors.getTempCByIndex(0);
Serial.print("Senzor1: ");
Serial.println(Senzor1);

thank you

2

You want to round to the nearest multiple of 0.5.

So first convert to an integral multiple:

int  half_degrees = (int) (Senzor1 * 2.0 + 0.5) ;  // 0.5 for unbiased rounding 
Senzor1 = half_degrees * 0.5 ;

Or combine in one line

  Senzor1 = 0.5 * (int) (Senzor1 * 2.0 + 0.5) ;
3

Thank you ,I will try ...

4

Or you can set the sensor to 9-bit precision which will give you half a degree accuracy.
Also, you should print the result like this:

Serial.println(Senzor1,1);

so that it only prints one fractional digit.

Pete