4 buttons problem.

Projects Programming
1

I tried to make a circuit with 4 buttons and 4 LED's.
When one LED should light but instead they are all powered at all time.
here is my code:

const int buttonPin1 = 8;
const int buttonPin2 = 9;
const int buttonPin3 = 10;
const int buttonPin4 = 11;
const int ledPin1 = 2;
const int ledPin2 = 3;
const int ledPin3 = 4;
const int ledPin4 = 5;
int buttonState1 = 0;
int buttonState2 = 0;
int buttonState3 = 0;
int buttonState4 = 0;
void setup() {
  pinMode(ledPin1, OUTPUT);
  pinMode(ledPin2, OUTPUT);
  pinMode(ledPin3, OUTPUT);
  pinMode(ledPin4, OUTPUT);
  pinMode(buttonPin1, INPUT);
  pinMode(buttonPin2, INPUT);
  pinMode(buttonPin3, INPUT);
  pinMode(buttonPin4, INPUT);
}
void loop() {
  buttonState1 = digitalRead(buttonPin1);
  buttonState2 = digitalRead(buttonPin2);
  buttonState3 = digitalRead(buttonPin3);
  buttonState4 = digitalRead(buttonPin4);
  if (buttonState1 == HIGH) {
    digitalWrite(ledPin1, HIGH);
    digitalWrite(ledPin2, LOW);
    digitalWrite(ledPin3, LOW);
    digitalWrite(ledPin4, LOW);
  }
  if (buttonState1 == LOW) {
    digitalWrite(ledPin1, LOW);
    digitalWrite(ledPin2, LOW);
    digitalWrite(ledPin3, LOW);
    digitalWrite(ledPin4, LOW);
  }
  if (buttonState2 == HIGH) {
    digitalWrite(ledPin1, LOW);
    digitalWrite(ledPin2, HIGH);
    digitalWrite(ledPin3, LOW);
    digitalWrite(ledPin4, LOW);
  }
  if (buttonState2 == LOW) {
    digitalWrite(ledPin1, LOW);
    digitalWrite(ledPin2, LOW);
    digitalWrite(ledPin3, LOW);
    digitalWrite(ledPin4, LOW);
  } 
  if (buttonState3 == HIGH) {
    digitalWrite(ledPin1, LOW);
    digitalWrite(ledPin2, LOW);
    digitalWrite(ledPin3, HIGH);
    digitalWrite(ledPin4, LOW);
  }
  if (buttonState3 == LOW) {
    digitalWrite(ledPin1, LOW);
    digitalWrite(ledPin2, LOW);
    digitalWrite(ledPin3, LOW);
    digitalWrite(ledPin4, LOW);
  }
  if (buttonState4 == HIGH) {
    digitalWrite(ledPin1, LOW);
    digitalWrite(ledPin2, LOW);
    digitalWrite(ledPin3, LOW);
    digitalWrite(ledPin4, HIGH);
  }
  if (buttonState4 == LOW) {
    digitalWrite(ledPin1, LOW);
    digitalWrite(ledPin2, LOW);
    digitalWrite(ledPin3, LOW);
    digitalWrite(ledPin4, LOW);
  }
  else {
    digitalWrite(ledPin1, LOW);
    digitalWrite(ledPin2, LOW);
    digitalWrite(ledPin3, LOW);
    digitalWrite(ledPin4, LOW);
}
}

There is a picture of my wiring attached.
hope you can help me :slight_smile:

foto.JPG

2

This is a simplified "echo" sketch, the LEDs follow the buttons, is that what you meant?

const int buttonPin1 = 8;
const int buttonPin2 = 9;
const int buttonPin3 = 10;
const int buttonPin4 = 11;

const int ledPin1 = 2;
const int ledPin2 = 3;
const int ledPin3 = 4;
const int ledPin4 = 5;

int buttonState1 = 0;
int buttonState2 = 0;
int buttonState3 = 0;
int buttonState4 = 0;

void setup() 
{
  pinMode(ledPin1, OUTPUT);
  pinMode(ledPin2, OUTPUT);
  pinMode(ledPin3, OUTPUT);
  pinMode(ledPin4, OUTPUT);

  pinMode(buttonPin1, INPUT);
  pinMode(buttonPin2, INPUT);
  pinMode(buttonPin3, INPUT);
  pinMode(buttonPin4, INPUT);
}

void loop() 
{
  buttonState1 = digitalRead(buttonPin1);
  buttonState2 = digitalRead(buttonPin2);
  buttonState3 = digitalRead(buttonPin3);
  buttonState4 = digitalRead(buttonPin4);

  digitalWrite(ledPin1, (buttonState1 == HIGH);
  digitalWrite(ledPin2, (buttonState2 == HIGH);
  digitalWrite(ledPin3, (buttonState3== HIGH);
  digitalWrite(ledPin4, (buttonState4 == HIGH);
}

Or do you want the first one to be pressed the only one to be on?

3

yeah I want the LED's to follow the buttons.

4

Please take some time to go through the tutorials about array's and for loops in C++

Can make the code far shorter.

5

but it doesn't work!

6

If you just copied and pasted the sketch, then you need to add the closing parenthesis to these.

digitalWrite(ledPin1, (buttonState1 == HIGH);
digitalWrite(ledPin2, (buttonState2 == HIGH);
digitalWrite(ledPin3, (buttonState3== HIGH);
digitalWrite(ledPin4, (buttonState4 == HIGH);

7

I don't see any resistors on those switches. That'll leave the input floating when they're off. Also, the switch ground bus isn't connected to the other ground bus.