4x3 Keypad with LCD display

Other Hardware Displays
1

hey , guys I have some project which involve in arduino code. I am a beginners for this code. Whenever I stored the value inside, when I pressed the keypad '#', it didn't stored the value inside. what shall I do? I stuck here. someone help.

here is my code :

#include <Keypad.h>
#include <LiquidCrystal.h>

#define Weight_Length 255
LiquidCrystal lcd (A0,A1,A2,A3,A4,A5);

char Data[Weight_Length];
char Weight;
byte data_count = 0;

float circumference;
int Kph;
int CB;

const byte rows =4;
const byte cols =3;
char keys[rows][cols]={
{'1','2','3'},
{'4','5','6'},
{'7','8','9'},
{'*','0','#'}
};

byte rowPins[rows] = {3,4,5,6};
byte colPins[cols] = {7,8,9};

Keypad kpd = Keypad(makeKeymap(keys), rowPins, colPins, rows, cols);

void setup() {
lcd.begin(16, 2);
lcd.println("ENTER WEIGHT ");
kpd.addEventListener(keypadEvent);
}

void loop() {
Weight = kpd.getKey();
if (Weight){
Data[data_count] = Weight;
lcd.setCursor(data_count ,1);
lcd.print(Data[data_count]);
data_count++;
}
}
// This can key in unlimited digits
//pass

void keypadEvent(KeypadEvent key){
switch (kpd.getState()){
case PRESSED:
if (key == '#'){
lcd.clear();
break;
}
}
}

sketch_jul19a.ino (966 Bytes)

2

Hi, and welcome.

Please read the guidelines on how to use the forum (click !).
It will teach you how to post tour code in the proper way, and a lot of other things to consider.

I'm not sure what you mean by 'stored inside'.
Do you mean you do not see the '#' on your LCD ?
Because that is correct, once you type that '#', the LCD's contents are erased.

Instead, go and process your variable called 'data', once you've registered the "#" and erased your display.

3

No , its not that, when i pressed the key '#'. it cant stored the previous integer that i typed in the void setup.

here is my code :

#include <Keypad.h>
#include <LiquidCrystal.h>

#define Weight_Length 255
LiquidCrystal lcd (A0,A1,A2,A3,A4,A5);

char Data[Weight_Length];
char Weight;
byte data_count = 0;
int a(13);
boolean blink = false;
boolean ledpin_state;

const byte rows =4;
const byte cols =3;
char keys[rows][cols]={
{'1','2','3'},
{'4','5','6'},
{'7','8','9'},
{'*','0','#'}
};

byte rowPins[rows] = {3,4,5,6};
byte colPins[cols] = {7,8,9};

Keypad kpd = Keypad(makeKeymap(keys), rowPins, colPins, rows, cols);

void setup() {
lcd.begin(16, 2);
lcd.println("ENTER WEIGHT ");
ledpin_state = digitalRead(a);
kpd.addEventListener(keypadEvent);
}

void loop() {
Weight = kpd.getKey();
if (Weight){
Data[data_count] = Weight;
lcd.setCursor(data_count ,1);
lcd.print(Data[data_count]);
data_count++;
}
}
// This can key in unlimited digits
//pass

void keypadEvent(KeypadEvent key){
switch (kpd.getState()){
case PRESSED:
a= Weight;
if (key == '#'){
lcd.clear();
ledpin_state = digitalRead(a);
digitalWrite(a,!digitalRead(a));
lcd.println("Weight = ");
lcd.setCursor (data_count ,1);
lcd.print(Data[data_count]);

break;

case RELEASED:
if (key == '#'){
digitalWrite(a,ledpin_state);
blink = false;
}
break;
}
}
}

4

Hi.

I can't help you.
I don't understand what you are trying to communicate.

But far worse: You did not read the link i gave you, and now you've started crossposting.

Goodbye.

5

So someone deleted your crosspost.

Here's 2 pieces of advice:

  • Take the advice given, and do something with it.[/li][/list]

  • What's this ?int a(13);

6

MAS3:

  1. What's this ?int a(13);
    [/quote]

That is valid C++. It defines an integer named "a" and initializes it with the value 13. It follows the same syntax as defining an object and passing one argument to the class's constructor.