Per the arduino support page, the 5V pin can be enabled by shorting the VUSB pads. I have soldered the pads together and powered the board via VIN with a 12V battery. The 5V pin is giving me 0V. Can someone confirm they have successfully done this operation? Have I damaged the board with the soldering iron?
According to the documentation page you linked, 5V power is available only if you have made that solder connection AND power the board via USB.
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Welcome to the forum.
Everything is open and online.
The Nano 33 BLE with pinout and schematic: https://store.arduino.cc/products/arduino-nano-33-ble.
The 5V from the USB can be passed on to the "5V" pin with the solder pad and 12V can be applied to "VIN". So far so good.
However, the board has no 5V itself. It makes 3.3V from the 12V, that's all. Only the 5V from the USB cable is 5V. Disconnect the USB cable and the 5V is gone.
What do you need 5V for ?
Maybe there is a other (better) solution.
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Jremington,
Thank you for the quick response. I think it comes down to our interpretation of the support page. It lists two bullets. I interpreted the bullets as OR and I believe you interpreted the bullets as AND. Before the jump, when usb power was applied, I dropped 4.3V across the 5V pin and ground. This led me to believe that it was an OR (||).
Koepel,
I don’t completely understand your response, are you saying that 5V output is only available when usb power is applied?
That is what Koepel and I are both saying. The operative word is AND.
Check the schematic diagram. The meaning of VUSB (and VBUS) should also be obvious to you.
The documentation is not just confusing, I say it is "wrong", well, at least it is "not right":
Yes, it appears confusing and could easily be interpreted as an OR rather than an AND.
Perhaps it should be clarified to add 'and' before the second point.
Thanks for the responses. I understand now.
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