AD 620 amplifier chip

I am make up a circuit using a AD620 amplifier chip I just wont to confirm pins. 1 and 8 power in what one is +,2 and 3 input,6 output of signal, 5- connected to ground and - input.

can some confirm if this is correct.

can some confirm if this is correct.

Nop.

See attached data sheet. Top of page 14 has it clearest.

AD620.pdf (436 KB)

is this better. 1 and 8 has a resistor ,2 and 3 input,6 output of signal, 5- ref (ground), 7 pw+, 4pw-.
reading speck sheets help LOL.

thanks for reply

Knowing how to read a datasheet is extremely important if you ever intend to do anything worth doing in electronics.
Also, proper spelling might help.

In response to your question, 5V goes to pin 7, and ground goes to pin 4. Your output will come out of pin 6. A resistor between pins 1 and 8 will set your gain. Your non-inverting input will go on pin 3 and your inverting input goes on pin 2. Your reference goes on pin 5, most of the diagrams just put that down to 5.

Seriously though, if you keep on asking questions like this (spelled improperly and clearly are refusing to do actual work) everybody is gonna…extremely dislike you.

and ground goes to pin 4.

Well no, pin 4 is the negative supply and pin 5 is the ground or signal reference.
Now if you bias the signal ground to half the single ended supply then you could consider pin 4 to be ground but from a supply point of view only.

OH! Yes yes. My bad
(I don't work with discrete op amps much)

funkyguy4000:
OH! Yes yes. My bad
(I don't work with discrete op amps much)

It's not an op amp, it's an instrumentation amplifier, which is something different.

thanks for info yes my spelling is a bit ruff, and what work am I refusing to do.
I am new to all of this stuff so give a newbie a chances.