I have the following multiplexer:
http://www.perturb.org/tmp/datasheet-2.pdf
I want to wire this up to control 8 LEDs. I'm not quite sure how to wire this up, can help me make sense of this schematic for me? Here is what I have:
Vdd I have wired to 5v. Voltage to run the chip itself
A, B, and C I have wired to digital pins 2, 3, and four respectively
I have four LEDs anodes wired to 0, 1, 2, and 3 and the cathodes connected through to ground.
What do I do with Vss, Vee, and the common in/out?
What do I do with Vss, Vee, and the common in/out?
Ground, ground, and your input line.
Multiplexers generally dont have a latch, so you will only be able to drive 1 LED at a time.
PS: And remember the series resistors before each LED.
I can't access that data sheet from work the web blockers won't let me.
You generally don't use a multiplexer for driving LEDs, especially an analogue one. Can you post your schematic.
Best guess: 4051b
Ooops I fixed the link. It is a HCF4051B chip.
I only need to drive one LED at a time, this is going to control a 7 segment thing. I want to make it circle around (1 segment at a time).
The problem with my 7 segment is that it has a common 5v, and each pin is then shorted to ground to make a segment light up. Is it even possible to use this chip to short to ground instead of to 5v?
Vdd = Positive Supply voltage (5v)
Vss = Negative Supply voltage (ground?)
Vee = Supply Voltage (no idea!)
I just want to short the output pins to ground to make my 7 segment light up.
Well you can use this chip but it is the wrong thing to do.
Vee to +5V
Vdd to +5V
Vss to ground.
Common input / output to ground
Y0 to Y7 - to a resistor then to the cathode of the segment.
anode of 7 seg display to +5v.
It is the wrong chip for this job because you can have between 120R and 365R on resistance between input and output.
You may need a chip like the 74hc138 which I think sinks current when a pin is actuated. The below link shows one in use.