Arduino Error: "too many initializers for 'char [3]'"

Using Arduino Programming Questions
#1

I am trying to code for a keypad and a beeper. I have used the code from various tutorials, and they all seem to work. However, I am getting the following error message:

too many initializers for ‘char [3]’

I don’t know what is causing this. Here is my code for anyone who wishes to help:

#include <Keypad.h>
int beeper = 4;

const byte ROWS = 4;
const byte COLS = 3;

char keys [ROWS] [COLS] = {
{“1”, “2”, “3”},
{“4”, “5”, “6”},
{“7”, “8”, “9”},
{"*", “0”, “#”}
};

byte rowPins[ROWS] = {47, 45, 43, 41};
byte colPins[COLS] = {39, 37, 35};

Keypad keypad = keypad(makeKeymap(keys), rowPins, colPins, ROWS, COLS);

void setup(){
Serial.begin(9600);
pinMode(beeper, OUTPUT);
}

void loop(){
char key = keypad.getKey();

if(key){
Serial.println(key);
digitalWrite(beeper, HIGH);
delay(25);
digitalWrite(beeper, LOW);
}
}

If anyone can help then it would be much appreciated!

#2

Don't use double quotes in your keys array, just simple quotes for characters

(Please read how to use the forum and correct your post using code Tags around your code)

#3