Normally you should use:
char A = {'h','e','l','l', 'o'};
Then addresses of A[0], A[1], A[3] should have consecutive numbers.
Apparently the compiler is free to change the order of putting things on the stack...
Groet, Koen.
Normally you should use:
char A = {'h','e','l','l', 'o'};
Then addresses of A[0], A[1], A[3] should have consecutive numbers.
Apparently the compiler is free to change the order of putting things on the stack...
Groet, Koen.