Arduino program for the pocket watch b

Projects Programming
1

I have a pocket watch b
I try to write a arduino program for thePocket watch b
I modified the bs2 sample to rebuild thearduino program
But the modified program could not work

Bs2 sample Code:

input 10'communication FROM Pocket Watch B
output 11'communication TO Pocket Watch B
input 12 'ALARMmonitoring pin
'Declare variables
ss var byte 'seconds
mm var byte 'minutes
hh var byte 'hours
dd var byte 'days
mo var byte 'months
yl var byte 'years low
yh var byte 'years high

HIGH 11 'ensure no spurious start bit
PAUSE 1000

SetTimeCommand: 'setto 6:30:00AM, June 3, 1997

SEROUT11,84,[$55,$00,$00,$1E,$06,$03,$06,$61]

ReadTimeCommand: 'seewhat time it is presently
SEROUT11,188,[$55,$02]
SERIN10,188,5000,[ss,mm,hh,dd,mo,yl]
DEBUG "Time: ",dec2 hh,":",dec2 mm,":",dec2 ss," ",dec2mo,"/",dec2 dd,"/19",dec2 yl, cr

Arduino program

#include<SoftwareSerial.h>
SoftwareSerial mySerial(10, 11); // RX, TX
//Declarevariables
int ss; //seconds
int mm; //minutes
int hh; //hours
int dd; //days
int mo; //months
int yl; //yearslow
int yh; //yearshigh

void setup()
{
Serial.begin(9600);
pinMode(10,INPUT);
pinMode(11,OUTPUT);
pinMode(12,INPUT);
}

void loop()
{
digitalWrite(11,HIGH);
delay(1000);
mySerial.print(95,HEX);
mySerial.print(00,HEX);
mySerial.print(00,HEX);
mySerial.print(30,HEX);
mySerial.print(06,HEX);
mySerial.print(03,HEX);
mySerial.print(06,HEX);
mySerial.print(97,HEX);
// delay(1000);
mySerial.print(95,HEX);
mySerial.print(02,HEX);
if (mySerial.available()>0)
{
ss=mySerial.read();
mm=mySerial.read();
hh=mySerial.read();
dd=mySerial.read();
mo=mySerial.read();
yl=mySerial.read();
}
Serial.print(hh);
Serial.print(mm);
Serial.print(ss);
Serial.print(yl);
Serial.print(mo);
Serial.print(dy);
}

2

But the modified program could not work

What did it do?
What didn't it do?

Why use "int" for seconds, minutes and hours etc?

Where are the code tags?

  mySerial.print(06,HEX);

What's the point of printing an octal value in hex? (there may be a clue as to what is going wrong)

SEROUT11,188,[$55,$02]

  mySerial.print(95,HEX);
  mySerial.print(02,HEX);

If those are meant to be equivalent, you may wish to review your hex to decimal arithmetic.
Or, specify the constants in hex (0x55), and let the compiler do the hard work.

3 
 if (mySerial.available()>0)
  {
   ss=mySerial.read();
   mm=mySerial.read();
   hh=mySerial.read();
   dd=mySerial.read();
   mo=mySerial.read();
   yl=mySerial.read();
  }

No. You know you have one (or more) bytes and you are reading six. You probably only have one byte.