Array Assignment showing % values

Projects Programming
1

Hello.

I am trying to assign an array"Locoadding[0]" to another array"textfield[0]" and want to display the value in the serial monitor it is showing %

Thanks in advance

char* TempLocoAddress[4] = {"1830", "3", "999", "4444"}; //Setting the Default loco addresses at the startup
char* LocoAddress[4] = {"1830", "3", "999", "4444"}; //Setting the Default loco addresses at the startup
char Locoadding[1][5] = {'\0'}; //Setting the Default loco addresses at the startup
#define TEXT_LEN 10
char textfield[TEXT_LEN + 1] = "";



#define maxLocos 4
void setup() {
  Serial.begin(9600);
  Locoadding[0][5] = "21234";
  textfield[0] = Locoadding[0][5];
  Serial.print ("Locoadding[0]: " );
  Serial.print(Locoadding[0][5]); // this is showing blank
  Serial.println ();

  addLocoAddressToArray(textfield[0]);
}

void loop() {

}
void addLocoAddressToArray(char LocoToAdd[]) {
  Serial.print ("locotoadd : " );
  Serial.print(LocoToAdd); \\ this one is also showing %
  Serial.println ();
  int k = 1;

  if (LocoToAdd != "") {

    LocoAddress[0] = LocoToAdd[0];
    for (int j = 0; j <= maxLocos - 1 ; j++)
    {
      Serial.print (" k ");
      Serial.print(k);
      Serial.println ();
      LocoAddress[k] = TempLocoAddress[j];
      k++;
      if (k == 3) {
        j = maxLocos;
      }
    }


    for (int i = 0; i <= maxLocos - 1  ; i++)
    {


      Serial.println ();
      Serial.print (i);
      Serial.print (" LocoAddress ");
      Serial.print (LocoAddress[i]);
      Serial.println ();

    }
  }
}
2

Operations like the following are not useful and do not do what you want.

  Locoadding[0][5] = "21234";

  1. Use the C-string functions like strcpy(), strcat(), memcpy() etc. to copy and manipulate C-strings (zero-terminated character arrays).

  2. Locoadding[] is too short. It must be 6 characters long to hold "21234" plus the zero terminator.

3

Thanks suggestion resolved the issue