Assistance with binary counter

[rramesh]

I am not very good at programming. I have from the net obtained a piece of code and modified it slightly to get what I want. Basically, I am trying to count upwards from 0 to 127 in binary.

At the bit level it seems to be working. However at the end of forming a new 7 bit number, I want to be able to take all those 7 bits and write it into an address string for further manipulation.

While my code does not throw any errors, I am not getting any output where I try to Serial print the address string.

The second question I have is when the program runs, in the serial monitor past the 100 0000 stage, I start to get a funny character leading the 7 bit number. Why is that?

Any help would be much appreciated.
Binary_Counter.ino (1.0 KB)

[UKHeliBob]

Why did you start a topic in the Uncategorised category of the forum when its description is

DO NOT CREATE TOPICS IN THIS CATEGORY

Your topic has been moved to the Programming category

Please post your code here rather than attaching it and please use code tags when you do

[kolaha]

@rramesh

in binary

all calculations are binary

[kolaha]

void setup() {
  Serial.begin(115200);
}

void loop() {
  static uint8_t Number = 0;
  for (uint8_t i = 8; i > 0; i--)
    Serial.print(Number & 1 << (i - 1));
  Serial.println();
  Number++;
  if (Number > 127)Number = 0;
  delay(500);
}

[rramesh]

@kolaha

void setup() {
  Serial.begin(115200);
}

void loop() {
  static uint8_t Number = 0;
  Serial.println(Number, BIN);
  Number += 1;
  if (Number > 127)Number = 0;
  delay(500);
}

Thank you for your reply.

I am afraid irrespective of the count number, I want the binary output appearing to be 7 bits long (padded with zeros if required). So a 2 should appear as 000 0010. Your code give it as just 10.

Once that problem is solved, could you also advice how I could get those 7 bits written into a an array of characters ( which I have called as address)?

Basically I am going to use this address to scan a for devices on a network and that is the end use. Just so that you know.

[kolaha]

already done.
and now with array
upd
wait, sometning wrong

[herbschwarz]

I think that 'Serial.print' suppresses leading zeros (ignores them) so '10' is actually '0000 0010', the same thing.

[rramesh]

Thank you for your reply.

While I understand the Serial.print suppresses the leading zeros, and I am okay with it not appearing on the serial monitor as I am using Serial.print merely to debug the code.

However, I need to be able to capture the the leading zeros to be able to write the entire 7 bit number into an array of 7 characters.

This array then forms the address of the device I intend to search for (during my scan). The scan itself will be done by reading each of the 7 characters and forming a high or a low pulse on a serial bus.

So if i have not confused you already, the leading zeros are important for me to ensure correct pulse formation when I do a device search.

[rramesh]

Yes there is a tiny error somewhere.
This is the output I am getting

00000000
00000001
00000020
00000021
00000400
00000401
00000420
00000421
00008000
00008001
00008020
00008021

Nearly there...

[kolaha]

char Adderes [8] = {0};
void setup() {
  Serial.begin(115200);
}

void loop() {
  static uint8_t Number = 0;
  for (uint8_t i = 8; i > 0; i--) {
    Serial.print(Number & 1 << i - 1?1:0);
    Adderes[i] = (Number & 1 << (i - 1))?1:0;
  }
  Serial.println();
  Number++;
  if (Number > 127)Number = 0;
  delay(500);
}

[rramesh]

Thank you . This is much better.

However, I have one more question.

I notice by putting it in a loop (8 times), you are serial.printing the number to form the 8 bit number. The same bit is there after stored in the address[i] position as well.
I get that.

Why is it that after the loop of 8 (modified to 7) is over, after your Serial.println command,
I am not able to print the contents of the entire address array with a
Serial.print(Adderes); command? << In fact this throws up an error.

So my question is how do I print the entire Adderes?

char Adderes [7] = {0};
void setup() 
{
  Serial.begin(115200);
}

void loop() {
  static uint8_t Number = 0;
  for (uint8_t i = 7; i > 0; i--) {
    Serial.print(Number & 1 << i - 1?1:0);
    Adderes[i] = (Number & 1 << (i - 1))?1:0;
  }
  Serial.println();
  
  **Serial.print(Adderes);** 
  
  Number++;
  if (Number > 127)Number = 0;
  delay(500);
}

[kolaha]

char Address [8] = {0};

void setup() {
  Serial.begin(115200);
}

void loop() {
  static uint8_t Number = 0;
  for (uint8_t i = 0; i < 8; i++) {
    bool Bit = Number & 1 << (7 - i);
    Serial.print(Bit);
    Address[i] = Bit;
  }
  Serial.println();
  Number++;
  if (Number > 127)Number = 0;
  for (uint8_t i = 0; i < 8; i++)Serial.print(Address[i], DEC);
  Serial.println("\r\n");
  delay(500);
}

[rramesh]

Perfect !! Just what I wanted.
Nice to be a part of an open source community where so much of expertise is handy so quickly.

Thank you so much .