Can i use this:
If not, which one can i use to charge that batteries?
Yes it can, but you have to set to correct charging current.
BillHo:
Yes it can, but you have to set to correct charging current.
How?
The resistor labeled "122" (1.2K) sets it at 1A. They have a chart on that page showing the various resistor/charge rates.
tsunamy_boy:
BillHo:
Yes it can, but you have to set to correct charging current.How?
Look at the Charge Table on the page, you have to change the value of the resistor Rprog
Since you are using 240mhA battery, your charge current change to 130mA so you have to change Rprog to 10K ohms
The resistor need to change was circle in RED
Thank you guys!
240mhA battery, your charge current change to 130mA
So this means that i always have to choose the lower value when i don't have the right value?
Also, can i charge this battery with that charger:
http://www.ebay.com/itm/BLC-2-Battery-for-Nokia-3310-3330-3510I-3320-5510-6800-6810-6650-3410-/360788753110?pt=LH_DefaultDomain_3&hash=item5400af7ad6
This is a 3.6V battery with 750mA
Yes, reference to the datasheet you can calculate the resistor base this formula IBat = VProg/RProg X 1200 (VPROG=1V)
tsunamy_boy:
Thank you guys!240mhA battery, your charge current change to 130mA
So this means that i always have to choose the lower value when i don't have the right value?
Also, can i charge this battery with that charger:
http://www.ebay.com/itm/BLC-2-Battery-for-Nokia-3310-3330-3510I-3320-5510-6800-6810-6650-3410-/360788753110?pt=LH_DefaultDomain_3&hash=item5400af7ad6
This is a 3.6V battery with 750mA
yes
So for the nokia battery.
Which is a 3.6V battery with 750mA.
I would have to do this calculation:
750 = 3.6 * 1200
R
(=) 3.6*1200 = 750
R
(=) 3.61200 = 750R
(=) 4320 = 750*R
(=) 750R = 4320
(=) R = 4320
750
(=) R = 5.76
So 5.76K resistor? Am I right?
No,
IBat = VProg/RProg X 1200 (VPROG=1V)
750mA = 0.75A
0.75 = (1) * 1200 / R
R = 1200/0.75
R = 1600 Ohms
R = 1.6K Ohms
So you have use 1.6K ohms resistor for RProg.
Thank you, but the usual lithium batteries are 3.7V and this one is 3.6V does that influences on the calculation?
I'm talking about this bat: http://www.ebay.com/itm/BLC-2-Battery-for-Nokia-3310-3330-3510I-3320-5510-6800-6810-6650-3410-/360788753110?pt=LH_DefaultDomain_3&hash=item5400af7ad6
I just want to make sure i don't blow anything on my hands 
3.7V (or 3.6V) is the "nominal" voltage of the battery. Lithium batteries are charged to 4.2V, and that peak voltage spec if the one you need to concern yourself with. I'm not going to flat out guarantee it's 4.2V for this particular battery, but more than likely it is and the charger should work with it fine.
Ok thank you guys for the help,
Have a great day