Better way to get all Service/Characteristics UUIDs?

Projects Programming
1

Hello everyone!

Long time user first time poster. Basically the premises is this: I want to dump all the Service/Characteristics UUIDs that I can connect to around me.

  Serial.print("Forming a connection to ");
    Serial.println(myDevice->getAddress().toString().c_str());
     BLEClient*  pClient  = BLEDevice::createClient();
     
    pClient->setClientCallbacks(new MyClientCallback());

    // Connect to the remove BLE Server.
    pClient->connect(myDevice);  // if you pass BLEAdvertisedDevice instead of address, it will be recognized type of peer device address (public or private)
    Serial.println(" - Connected to server");
    pClient->setMTU(517); //set client to request maximum MTU from server (default is 23 otherwise)
          
 
      using namespace std;
      auto servicesMap = pClient->getServices(); // got services map how to use
   
    std::map<std::string, BLERemoteService*>::iterator itr;
      for (itr=servicesMap->begin(); itr!=servicesMap->end(); itr++){
      result+=myDevice->getAddress().toString().c_str();
      result+=",\n";
      result+=itr->first.c_str();
      result+=",\n";
      }
      
     Serial.println("Map succesfully compiled");
     Serial.print(result);

This is great when I can connect the the device but if I can't it just sits there.

Forming a connection to 24:20:00:e7:45:c7
first print
second print
 - Created client
 - Connected to server

First I understand you cannot connect to all devices and interrogate them, however I can't seem to find a way to do a if(can connect) type of statement...

Few questions here
First is there a better way to attempt to do this that IDK about??

Second is there a way to do a timeout so the program stops if it cannot connect and map the Service/Characteristics UUIDs?

Is there a way to just print out the ServiceUUID maybe if one is there? Like printing this statement:
BLERemoteService* pRemoteService = pClient->getService(serviceUUID);

But that would just be the advertized serviceUUID wouldn't it?

Thanks!

2

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