i am sending data on serial is 3 when is display is this 3 but i can conver in bninary then become 00110011 instead 00000011.and when i invert it then i got 01100110 instead of 11111100 ,why so ?
That is the ASCII code for the number 3.
In hex it's 0x33.
Just subtract 0x30.
Yes, that's puzzling
Maybe something wrong in the code you didn't post.
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maybe inverting is wrong idea to convert an ASCII symbol "3" to integer value = 3.
either you replace Serial.print(3); by Serial.write(3); in sender
or subtract 48(0x30 or '0') from received byte - int IntegerNumber =Serial.read()-48;
yes ,it is ascii ,i think it make the ascii value but how it inverting ?please help ,me
noting in the code,code is simple .
void setup()
{
Serial.begin(2400);
}
void loop()
{
int intValue = 1234;
Serial.println(intValue);
delay(1000);
}
Where is the number 3 and where do you invert it.
Your code only prints 1234
this is 51 in decimal_ where you got this?
00110011
01100110
you shifting, not inverting
yes ,i want to invert this value
Do an XOR with 0xFF
A = B^0xFF; // A will be the invert of B
a=~a
its outoput on MCU ,m not shifting this is the output of MCU and CRO
if i will do the xor of 3 then 3= 00110011 xor 11111111 = 11001100 it become 204 but answer that i am got from MCU is 102
all data are not shfited in same way like for 1,2,3,4,5,6,7& 8 digit
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