b = 1 << 1 | 1;
Here you're assigning b to 0... temp times.
Try this:
for(byte i = 0; i < temp; i++)
{
b = b | (1 << i);
}
There, every time the loop runs, b gets a 1 in one more place over.
b = 1 << 1 | 1;
Here you're assigning b to 0... temp times.
Try this:
for(byte i = 0; i < temp; i++)
{
b = b | (1 << i);
}
There, every time the loop runs, b gets a 1 in one more place over.