After a slight redesign here it is, the trick is to getting the transistors to fully switch off not to waste current, unlike polymorphs circuit, mine is higher powered for 300ma LEDs, using a 12v supply placing leds in series might be the way...
Erm, context?
Firstly, what are you talking about.
Secondly, all that and you still have 145uA "leakage" current? Wouldn't a low-side FET be easier and better as well?
Rob
No bjt's only lol...
5v goes out your 12v takes over!
MarkT:
Erm, context?
Hi, have you built the circuit?
If all you are relying on is a computer simulation, sorry nothing like the real thing.
I presume you have a load powered by 12v derived from the mains supply, it is also charging the battery.
If the load current is not too high, just use diode switching to keep battery power applied.
Please a REAL circuit diagram please, not the simulata one. Show battery and supply and load.
Tom..... 
TomGeorge:
Hi, have you built the circuit?
If all you are relying on is a computer simulation, sorry nothing like the real thing.I presume you have a load powered by 12v derived from the mains supply, it is also charging the battery.
If the load current is not too high, just use diode switching to keep battery power applied.
Please a REAL circuit diagram please, not the simulata one. Show battery and supply and load.Tom.....
How's it different to the real thing?
How's it not a REAL circuit diagram?
Hi.
What does the 5V source represent?
What does the 14.5V source represent?
Where is the load?
Show me a circuit please with batteries , your actual power source, your actual load.
Sorry, but simulations are like working things out in your mind/brain, put them into practice and find all the things that you didn't think of, wasn't put in the simulation.
When you are looking at uA, even tolerance of components will probably upset calculations.
Tom.......
oops sorry [soapbox] [/soapbox] (damn got to remember to take the effort to use the soapbox tags.)
Tom.....
The 5v source could be usb, a 5v dc plug pack, a solar cell,. The 12v is a lead acid battery.
Now does the circuit make sense? 5v goes out , circuit comes to life.