PeterH:
Watson91:
As to the reason I have the code set up to AvgRPM * 10 * 60 / 2. With a pulse at 60Hz, I should receive 6 falling edges every 10ms. If so my AvgRPM = 6. 6 * 10 * 60 / 2 = 1800 RPM which if I'm correct should be the RPM of a 60Hz frequency. Please correct me if I am approaching this the wrong way.A 60 Hz pulse corresponds to how many rpm?
60 pulses per second equals 3600 pulses per minute. If you are counting ignition pulses on one cylinder of a four-stroke engine you will get one pulse every two revolutions so that corresponds to 7200 rpm. Am I misunderstanding your setup?
I agree that I am somewhat confused by this reading also. I originally calculated what you are telling me it should be. When I hooked the oscilloscope to the engine signal I was receiving a 60Hz frequency at idle of the emitter leg of my signal conditioning. Idle of this briggs should roughly be around 1800 and 3200 is at the top of our RPM band. So, maybe there is some misunderstanding in what I was reading or I had something hooked up wrong.
But, according to the values you gave me which is AvgRPM * 10 * 60 * 2 this will be 7200 RPM.
If 60Hz AvgRPM = 6, 6 * 10 * 60 * 2 = 7200