Buddy.
I did mention it on your other thread Buddys LED project but if I were you I would ditch the Arduino Shiftout info and look at these three links. They helped me to connect more than one shift register and after looking at the code and applying my gi-normous brainpower (LOL) I saw how to turn on the LED,s in the order that I wanted to. I am at work now (hey boss I'm on a lunch break, ok….) but later I will put a bit of info together and post it for you if you are still having trouble,
Pedro
http://tronixstuff.wordpress.com/2010/04/30/getting-started-with-arduino-chapter-four/
http://bildr.org/2011/02/74hc595/
p.s. - In the meantime try this code for two shift registers
int dataPin = 2; //Define which pins will be used for the Shift Register control
int latchPin = 3;
int clockPin = 4;
int seq1[14] = {1,2,4,8,16,32,64,128,64,32,16,8,4,2}; //The array for storing the
// byte #1 value
int seq2[14] = {128,64,32,16,8,4,2,1,2,4,8,16,32,64}; //The array for storing the
// byte #2 value
void setup()
{
pinMode(dataPin, OUTPUT); //Configure each IO Pin
pinMode(latchPin, OUTPUT);
pinMode(clockPin, OUTPUT);
}
void loop()
{
for (int x = 0; x < 14; x++) //Array Index
{
digitalWrite(latchPin, LOW); //Pull latch LOW to start sending data
shiftOut(dataPin, clockPin, MSBFIRST, seq1[x]); //Send the data byte 1
shiftOut(dataPin, clockPin, MSBFIRST, seq2[x]); //Send the data byte 2
digitalWrite(latchPin, HIGH); //Pull latch HIGH to stop sending data
delay(75);
}
}