A simple google search gave me this: The burden is 1 mA per amp so the formulas are here: https://5lrorwxhmqqiiik.leadongcdn.com/ZMCT118F+specification-aidilBqoKomRilSnpomjnkp.pdf . Since it is a CT the burden as I believe you are calculating is correct. One bit of information that may mess you up is the output is not DC it is AC. So to use with the arduino you need to rectify it and use a low pass filter to convert to DC. This is just a little extra information as you did not say if it was a AC or DC application. This response is to help you get started in solving your problem, not solve it for you.
Good Luck & Have Fun!
Gil
1x CT sensor SCT-013-000
1x Burden resistor 18 Ohms if supply voltage is 3.3V or 33 Ohms if supply voltage is 5V
2x 470kOhm (for voltage divider, any matching value resistor pair down to 10K)
1x 10uF capacitor
mY QUESTION IS WITH ANALOGREAD VALUES
If i use 3.3v supply voltage, then what is analog read resolution(0 -> ???????? == 0 -> 3.3v)plz suggest
If i use 5v supply voltage, then what is analog read resolution(0 -> 1023 == 0 -> 5v)
Second if there is little difference in BURDEN RESISTOR value then what will be the effect at analog output values? Like
a) if 20ohms or 22 ohms are used instead of 18ohm
b) if 30 ohm or 36 ohm are used instead of 33ohm.
It sounds like it's talking about using 3.3 or 5v Arduinos. If you use the default Arduino ADC setting that uses the supply voltage as the reference then the resolution is 3.3/1024 or 5/1024.
If you were to use the internal voltage reference (and adjust the bias voltage) then it'll be 1.1/1024 for both, but then you only have a 1.1v working window.
The higher the burden resistor the higher the voltage output per amp. Deviating from the recommended values may give false readings (check the datasheet). Operating without a burden resistor may result in Arduino destroying voltages.