This motor has a long (0.365" or 9.27 mm), D-shaped metal output shaft that matches the Pololu wheel 42x19mm and 32x7mm. The brass faceplate has two mounting holes threaded for M1.6 screws (1.6 mm diameter, 0.35 mm thread pitch), or you can use the mounting bracket or extended mounting bracket, which are specifically designed to securely mount the gearmotor while enclosing the exposed gears. We recommend the extended mounting bracket for wheels with recessed hubs, such as the wheel 42×19 mm.
Specification
13000 rpm @ No load
50:1 Gear ratio
260 rpm @ 6V
40mA @ 6V
360mA stall current @ 6V
10 oz inches torque @ 6V
it is stated 13000rpm @ no load, wow it is fast!
but it is only 260rpm @ 6V, what it means? why not 13000rpm?
what it means 10 oz inches torque?
what it means 360 mA stall current?
Thank you so much for answering this newbie questions.
13000 rpm @ No load 50:1 Gear ratio
260 rpm @ 6V
40mA @ 6V
360mA stall current @ 6V
10 oz inches torque @ 6V
Divide the 13,000 by the 50:1 gear ration and see what speed you get at the output of the gear reduction shaft. And yes you should be able to reverse rotation direction with either a H-drive motor controller or other means to reverse the polarity of the applied voltage to the motor.
That motor is a two part assembly, a motor and a output reduction gear head. So while the motor is turning very fast, after the gear reduction the shaft is turning only 1/50 of the speed of the motor.
creativen:
So in fact if I modify the motor (remove the gear parts) then I can 13000rpm?
Yes, I guess, and if you don't actually attach anything mechanical to the motor. Recall that the max speed is rated when unloaded, where in reality we almost always use motors with some kind of load attached them even if just a fan blade, and the mechanical load will reduce the speed of the motor.
And it would be far cheaper just to buy a motor rather then buy a motor/gear reduction assembly just to then remove the gear reduction?
