First, I apologize for inadvertently cross-posting my reply to a reply on another forum. In the past I have posted on this forum in the hopes that it will be moved by an administrator to the appropriate forum.
This is my question: I am running a board on battery power. I am using it to collect data. I want to change batteries -but I don't want to interrupt the data input. My board has two, five volt vins. I want to attach the fresh battery without disconnecting the discharged battery (which would power-off the board). Can I have two battery packs attached to the board at the same time? If so, I can then remove the discharged battery pack for recharging, without interrupting the data input. The board's internal power regulator will keep it from overloading, yes?
-through just one, 5vin pin, or even the cable port, alone? Looks simple. I build the Schottky diode circuit with two battery terminals and splice a micro USB for connection to the board, that right? Before I try it, is there a video I can look at?
Normally you CAN connect the batteries in parallel temporarily. Without the diodes Larry shows, the dying batteries will drain the fresh batteries but a few (or several) seconds shouldn't hurt much.
My home thermostat loses its programming and day/time when I change the batteries so I bought a battery holder so I can connect temporary batteries while changing. (This means I'll need 2 fresh sets of batteries).
I haven't tried it yet and I'll need to solder some tabs (or something) to make an easier connection with allegator clips.
When I changed the batteries a couple of months ago, I temporarily connected a 10,000uF capacitor to hold the voltage while I quickly changed batteries, and that worked. (IIRC, I charged the capacitor with the fresh batteries first.) But the extra battery solution should work better.
The internal power circuit is intended to protect the board. It is not a feature.
Let me check my concepts; I am aware of three types of transistors: MOSFET, Schottky, and amplifier transistors.
- The diode you select needs to be able to pass the current expected.
Which board is this?
Is it a custom board?
Guru! Exceptional video. Now, I have to look at Schottky data sheets to pick the right type...
Watching the video, I was reminded of a strange fact. An ordinary magnetic relay in high state is actually alternating high/low. A connected led is blinking, but at a rate too rapid for the eye to notice. It has to do with the frequency of the power supply. True?
Arduino Micro I ordered a few years ago. First time powering the board off the data cable and desktop.
- Do not understand what you are saying, please reword.
The micro has only one Vin NOT two and it needs a voltage between 7V and 12V
Where do you see two Vins?
I'm reading a pinout diagram. I can't read anything on the board, itself, not even with a magnifying glass. Another reason to build a Schottky adapter for two battery packs...
Input voltage is a sine wave. The Schottky diode "shaves" half the wave, smoothes it, so to speak.
The rapid high/low relay effect can be controlled for applications such as automobile turn signals. Good thing.
- I am confused, why are you saying Input voltage is a sine wave ?
The video is rubbish. Especially someone with the skill level that needs the explanation will be more confused by it, as is demonstrated here above.
I suspect the 2 Vins are Vin and 5V. Arduino advises against using the 5V pin as input.
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