Well, you know the term charlieplexing, so presumably you've done some searches.
You simply need to attach opposing (back-to-back) pairs of diodes between all possible combinations of I/O pins.
Charlieplexing allows you to light n squared minus n LEDs, where n is the number of pins.
So, for 49 LEDs, you'll need at least eight pins.
http://en.wikipedia.org/wiki/Charlieplexing
you've probably already seen.
What more do you need to know?
Is it the hardware or the software you need to know more about?
its the hardware. Having known the theory, I dont understand how to lay out the remainder of the circuit after the first 14 LEDs.
so at the moment I have 2 rows of 7 LED's, wired in opposing directions, if i were to alternate again for the third row of LEDs surely it would react in the same way as the 1st row would, or maybe not function at all since the LEDs in row one are a quicker route.
heres a pic of what I have:
I also found this, but its so large I find it quite daunting and I don't really know which ones I should remove to adapt it to my needs..
I'm not sure you do understand the theory.
The progression goes (from n=2) 2, 6, 12, 20, 30, 42..
The "first 14" doesn't come into it.
So, for pins 0, 1, 2, 3.
Pairs across (0,1), (1, 2), (2, 3) = three LED pairs = 6 LEDs
Then a pair across (0, 2), (0, 3) = two LED pairs = 4 LEDs
And a pair across (1, 3) = one LED pair = 2 LEDs