Coding Simultaneous Output to Neopixel and an LED

Other Hardware LEDs and Multiplexing
14

So, I actually managed to get the LEDs to initiate simultaneously with the NeoPixel, using the millis() function.

@Grumpy_Mike I suppose that the remedy you just prescribed would result in the same.

My issue is, and I realize that I did not specify this prior, that the LED stays on for as long as it takes for the NeoPixel to complete its pulse (which I defined as 3 seconds). I actually want the LED to stay on for about 1 second and the NeoPixel pulse cycle to complete after 3 seconds.

I attempted to code the Neopixel pulse with a separate millis() clause; however, the LED and neopixel duration still seem set to complete over the same time. I also tried to replace the delay(15) within the pulse codes with a millis() condition; however, this would simply prevent any of the components from working in the circuit (perhaps it was written incorrectly).

Here is a copy of the [void loop(void)] code that has the LED on as long as the NeoPixel takes to pulse.

void loop(void)
{
  uint8_t len = readPacket(&bleuart, 500);
  if (len == 0) return;
   
  if (packetbuffer[1] == 'B') {
    uint8_t buttnum = packetbuffer[2] - '0';
    boolean pressed = packetbuffer[3] - '0';

    unsigned long currentMillis = millis();
    
    if (pressed) 
    {
      if(buttnum == 5) {
        //Serial.println("button1");
        digitalWrite(ledPinON, HIGH);
        brightenON();
        darkenON();
      }

      if((buttnum == 5) && (currentMillis - previousMillis >= LEDtime)) {
        //delay(1000);
        digitalWrite(ledPinON,LOW);
        //previousMillis = currentMillis;
      } 
      
      if(buttnum == 6){
        //Serial.println("button2");
        digitalWrite(ledPinOFF, HIGH);
        
        brightenOFF();
        darkenOFF();
      }

      if((buttnum == 6) && (currentMillis - previousMillis >= LEDtime)) {
        //delay(1000);
        digitalWrite(ledPinOFF,LOW);
        previousMillis = currentMillis;
      }
    }
  }
}
 

void brightenON() {
  uint16_t i, j;

  for (j = 0; j < 64; j++) {
    for (i = 0; i < strip.numPixels(); i++) {
      strip.setPixelColor(i, j, 0, 0, 0);
    }
    strip.show();
    delay(15);
  }
}

void darkenON() {
  Serial.begin(9600);
  uint16_t i, j;

  for (j = 64; j > 0; j--) {
    for (i = 0; i < strip.numPixels(); i++) {
      strip.setPixelColor(i, j, 0, 0, 0);
    }
    strip.show();
    delay(15);
    Serial.println(j);
  }
}

void brightenOFF() {
  uint16_t i, j;

  for (j = 0; j < 64; j++) {
    for (i = 0; i < strip.numPixels(); i++) {
      strip.setPixelColor(i, 0, j, 0, 0);
    }
    strip.show();
    delay(15);
  }
}

void darkenOFF() {
  Serial.begin(9600);
  uint16_t i, j;

  for (j = 64; j > 0; j--) {
    for (i = 0; i < strip.numPixels(); i++) {
      strip.setPixelColor(i, 0, j, 0, 0);
    }
    strip.show();
    delay(15);
    Serial.println(j);
  }
}

So I suppose in summary, my revised question is: how do I make it so that the LED and neoPixel turn on simultaneously, provided that the LED remain on for 1 second and the neoPixel pulse through a period of 3 seconds?