Comparing analog signals

Projects General Guidance
35 
int analogPin1 = A5;
int analogPin2 = A4;
int raw = 0;
int Vin = 5;
int redLed = 8;
int greenLed = 12;
float Vout = 0;
float R1 = 1000;
float R2 = 0;
float R3 = 1000;
float R4 = 0;
float buffer = 0;

void setup()
{
 Serial.begin(9600);
 pinMode(redLed, OUTPUT);
 pinMode(greenLed, OUTPUT);
}

void loop()
{
  raw = analogRead(analogPin1);
  if(raw){
    buffer = raw * Vin;
    Vout = (buffer)/1024.0;
    buffer = (Vin/Vout) - 1;
    R2= R1 * buffer;
    Serial.print("Vout: ");
    Serial.println(Vout);
    Serial.print("R2: ");
    Serial.println(R2);
    delay(1000);
  raw = analogRead(analogPin2);
  if(raw){
    buffer = raw * Vin;
    Vout = (buffer)/1024.0;
    buffer = (Vin/Vout) - 1;
    R4= R3 * buffer;
    Serial.print("Vout: ");
    Serial.println(Vout);
    Serial.print("R4: ");
    Serial.println(R4);
    delay(1000);
  if(R2 == 1503.67) 
    digitalWrite(redLed, HIGH);
    

}
}
}

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image1091×611 93 KB

I understand this code is a bit redundant as I have two of the same known values, a third other resistor, and the pot. Basically what is happening is that its reading two analog values at once and prints them. I tossed in a quick function to try and get the LED to work but it does not work at the moment. Like I said, I know this is a bit cumbersome but it is helping me understand what is going on a bit better. Any insight would be appreciated.