Compiling errors

Please I need your help I want to finish my project but just the code is remaining .when I try to compile the code it gives me one error or another,I don’t understand what am meant to correct am using Arduino/ genuino uno board. And also IRremote library.if you could help me cross-check for my errors.here is d code below

#include <IRremote.h>
#include <avr/interrupt.h>
const int RECV_PIN=5;

#define  code1 16718055 //button 2
#define  code2 16730805//button 8
#define  code3 16716015 //button 4
#define  code4 16734885 //button 6
#define  code5 16726215 //button 5

  IRrecv irrecv(RECV_PIN);
  decode_results results;

void setup()
{
  irrecv.enableIRIn();
  pinmode (12,output);
  pinmode (11,output);
  pinmode (10,output);
  pinmode (9,output); 
}

void loop() {
  if irrecv.decode (&results)
  unsigned int value=results.value;
  switch [value]{
  case code1;
  digitalwrite(12,HIGH);
  digitalwrite(11,LOW);
  digitalwrite(10,LOW);
  digitalwrite(9,HIGH);
  break;
  
  case code2;
  digitalwrite(12,LOW);
  digitalwrite(11,HIGH);
  digitalwrite(10,HIGH);
  digitalwrite(9,LOW);
  break;
  
  case code3;
  digitalwrite(12,HIGH);
  digitalwrite(11,LOW);
  digitalwrite(10,LOW);
  digitalwrite(9,LOW);
  break;
  
  case code4;
  digitalwrite(12,HIGH);
  digitalwrite(11,HIGH);
  digitalwrite(10,HIGH);
  digitalwrite(9,LOW);
  break;
  
  case code5;
  digitalwrite(12,LOW);
  digitalwrite(11,LOW);
  digitalwrite(10,LOW);
  digitalwrite(9,LOW);
  break;
  }
  irrecv.resume()
}
    case code1;

Cases should end with a colon not a semicolon

 pinmode (12, output);

pinmode() is not the same as pinMode()
output is not the same as OUTPUT

  if irrecv.decode (&results)

Check the syntax of the if statement

  switch [value]

The [ and ] should be ( and )

      digitalwrite(12, HIGH);

digitalwrite is not the same as digitalWrite

  irrecv.resume()

Missing semicolon

  switch (value)

value is declared in the code block of the preceding if command and is, therefore, out of scope here

Apart from those errors the code looks OK but I did not look at its logic

To save time, you could've simply posted the errors you saw.

UKheliBob
What is the syntax of IF statement

And for the last error you talked about I don't understand could u please expanciate.

What is the syntax of IF statement

if/else statement courtesy of Mr Google

And for the last error you talked about I don't understand could u please expanciate.

Which one ? I added several over a short period of time

UKHeliBob:
Which one ? I added several over a short period of time

Dollars to donuts, it's the scope one....

void loop() {
  if irrecv.decode (&results)
  unsigned int value=results.value;
  switch (value){
    //snip - lots of bad code as discussed elsewhere
  }
}

If what you meant was:

void loop() {
  if irrecv.decode (&results) {
  unsigned int value=results.value;
}
  switch (value){
    //snip - lots of bad code as discussed elsewhere
  }
}

when you try to switch on value, it will complain that value is undefined, because it's no longer in scope, as you declared it inside a block, but you are no longer in said block.

I suspect that what you wanted, though was something like this - because if you haven't set value, the switch/case statement is meaningless, and you probably don't want to run it at all.

void loop() {
  if (irrecv.decode(&results)) {
  unsigned int value=results.value;
  switch (value){
    //snip - lots of bad code as discussed elsewhere
  }
}
}

Others have described the many other issues with your code.

But another error came up it says- "value" not declared in this scope.
What do I do in this .

if irrecv.decode (&results)
  unsigned int value=results.value;
  switch [value]{

switch [value] Oops

Hi guys thank you my problem as been solved the last error was this;

if irrecv.decode (&results)
unsigned int value=results.value;
switch [value]{

Instead of;

if irrecv.decode (&results)
switch (results.value){

  unsigned int value=results.value;

The value member of the struct that results is an instance of is NOT an unsigned int. Use the proper type to uselessly store a copy of the value in results.value.