No, because serial sends the low-order (LSB) bits first. If you were only sending 7 bits that would account for it. The eighth bit (the stop bit) is a 1, so that would account for the 1 at the end (the high-order bit).
No, because serial sends the low-order (LSB) bits first. If you were only sending 7 bits that would account for it. The eighth bit (the stop bit) is a 1, so that would account for the 1 at the end (the high-order bit).