I am having a 12 volt 1300mAh rechargable battery connected to the output of boost converter having 13volt output(4.2 volt 1ah battery is input)....should i connect a resistor in parallel in output terminals of the converter and then connect it in parallel to 12v rechargable battery or should i connect it without resistor....and what value of resistor should i take ???
Unless your prepared to reveal what type of "12 volt 1300Ah rechargable battery" your attempting to charge no one will be able to answer your question.
Lead acid type gel based battery
should i connect a resistor in parallel in output terminals
Maybe a series resistor... A series resistor is a reasonable way to limist the current to "trickle charge" a battery.
But, but a "real" battery charger will have more circuitry to limit the current when the battery is low/dead, while still delivering enough current to charge quickly, and also something to prevent over-charging.
I am having a 12 volt 1300Ah rechargable battery connected to the output of boost converter having 13volt output(4.2 volt 1ah battery is input)....
If I understand you, you are trying to charge the "bigger" batter with the "smaller" battery. That won't work unless the larger battery is only slightly-discharged because the smaller battery doesn't store enough energy -
12 x 1.3 = 15.6 Watt-hours
1.2 x 1 = 4.2 Watt-hours
(And the energy-transfer isn't 100% efficient.)
Glad we know its a Lead Acid battery.
However before we go any further, do you really mean a 1300Ah battery ?
(i.e a battery that can deliver 1A for 1300 Hours)
1300Ah is big, most car batteries are in the 40Ah to 80Ah region.
And you might want to help us a bit more and say why you want to do this.
Oops sorry for my mistake.....its actually 1300mah or 1.3Ah battery....and im doing a project on boost converter battery charger using a 4.2 v battery as source
DVDdoug:
Maybe a series resistor... A series resistor is a reasonable way to limist the current to "trickle charge" a battery.But, but a "real" battery charger will have more circuitry to limit the current when the battery is low/dead, while still delivering enough current to charge quickly, and also something to prevent over-charging.
If I understand you, you are trying to charge the "bigger" batter with the "smaller" battery. That won't work unless the larger battery is only slightly-discharged because the smaller battery doesn't store enough energy -12 x 1.3 = 15.6 Watt-hours
1.2 x 1 = 4.2 Watt-hours(And the energy-transfer isn't 100% efficient.)
ut a boost converter must have always a load connected at its output terminals.....what i intend to ask here is that should i consider the battery as load itself ??? Or do i have to connect a resistor at the output of boost converter and then connect it in parallel to battery???
DVDdoug:
Maybe a series resistor... A series resistor is a reasonable way to limist the current to "trickle charge" a battery.But, but a "real" battery charger will have more circuitry to limit the current when the battery is low/dead, while still delivering enough current to charge quickly, and also something to prevent over-charging.
If I understand you, you are trying to charge the "bigger" batter with the "smaller" battery. That won't work unless the larger battery is only slightly-discharged because the smaller battery doesn't store enough energy -12 x 1.3 = 15.6 Watt-hours
1.2 x 1 = 4.2 Watt-hours(And the energy-transfer isn't 100% efficient.)
But a boost converter must have always a load connected at its output terminals.....what i intend to ask here is that should i consider the battery as load itself ??? Or do i have to connect a resistor at the output of boost converter and then connect it in parallel to battery???