Const char foo[] = "gives me an error"

[johnwasser]

@gfvalvo

The 'foo' member of myObj1 and myObj2 both point to the same memory location rather than their own character string as you might expect with copy-construction.

In my experience, the compiler optimizes string literals by only making one copy of each unique string. If you add two lines:

void setup()
{
  Serial.begin(115200);
  delay(1000);
  Serial.println((uint16_t)myObj1.foo, HEX);
  Serial.println((uint16_t)myObj2.foo, HEX);
  Serial.println((uint16_t)"hello world", HEX);
  Serial.println((uint16_t)"hello world", HEX);
}

You will see that 117 gets displayed four times.