Hello! I'm having trouble displaying continuous digit in my LCD.
I need to display the number of sensor selected by the user.
The display is ok when I display 6 single digits on line 1 and 3 single digits plus 3 double digits on line 2.
Nos.1,2,3,4,5,6,
_7,8,9,10,11,12?
and it's not ok when there's a double digit in line 1.
Nos.1,2,3,101112
should be
Nos.1,2,3,10,11,
_12?
This is my code:
for(int i = 0; i <= 11; i++){
int x=0;
int y=0;
if(fan[i] != 0){
if(i <= 5){
x=4+(2*i);
y=0;
}
else{
if(i <= 9){
x=(2*i)-11;
}
else{
x=(3*i)-20;
}
y=1;
}
Serial.print("x "); Serial.println(x);
// Serial.print("y "); Serial.println(y);
lcd.setCursor(x,y);
lcd.print(fan[i]);
if(fan[i+1] != 0){
lcd.print(",");
}
else{
lcd.print("?");
}
}
}
I think the problem is how will I set the cursor from line 1 to line 2 if there's no space left?
use
lcd.setCursor()
inly once per line and then print the array with commas without using the setCursor() function inside that loop.
I need setCursor() because I don't know when the selected sensor number exceed the line?
example:
Nos.1,2,10,11,
_12?
vs.
Nos.1,2,3,4,5,
_10,11,12?
ok, then do like this
set cursor
wil print like this:
1, 2, 3, 4, 5, 6,11,14,15
Then I cannot display all numbers
There are 12 sensors, if I do that I can only display up to
Nos._1,_2,_3,_4,
_5,_6,_7,_8,_9,1
This is my new code:
int x=0;
int y=0;
for(int i = 0; i <= 11; i++){
if(fan[i] != 0){
if(fan[i] <= 9){ // single digit
if(i == 0){
x=4;
}
else{
if(y == 0 && x < 14){ // line1
x=4+(2*i);
}
else{
x=(2*i)-11;
y=1;
}
}
}
else{ // double
if(y == 0 && x < 12){ // line1
x=2+(3*i);
}
else{
x=(3*i)-20;
y=1;
}
}
Serial.print("i "); Serial.println(i);
Serial.print("x "); Serial.println(x);
Serial.print("y "); Serial.println(y);
Serial.println("----");
lcd.setCursor(x,y);
lcd.print(fan[i]);
if(fan[i+1] != 0){
lcd.print(",");
}
else{
lcd.print("?");
}
}
}
This is the algorithm:
Last fan?
Single?
Single, Line1?
Double?
Double, Line1?
but there's still a problem when I display 2digits in line1
arduinoTime:
There are 12 sensors, if I do that I can only display up to
how about
char sensors[12] = { 'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L'};
Why are you manually setting the cursor, let the code do the work.
Set the cursor to display on line 1 and/or line 2, at column 4, and let the code take over.
HazardsMind:
Set the cursor to display on line 1 and/or line 2, at column 4, and let the code take over.
it appears he is overflowing the available space on the display, no matter how he gets there.
He doesn't need the blank spaces and the commas, he can use one or the other to separate them if needed, but not both. I like to use '|' as a separator.
"nos. 1|2|3|4|5|6" full, 16 columns used 13 column used
system
September 10, 2014, 4:31pm
11
Here is an idea to try - count the number of characters currently on line.
void TestLCD(void)
{
lcd.clear();
#define SENSORS 120
int iLine1Count = 0;
bool bLine2 = false;
int x=0;
int y=0;
for(int i = 0; i <= SENSORS; i++){
if(i < 10) // single digit
iLine1Count++;
else
iLine1Count += 2; // double
// add spaces etc. here
if(iLine1Count < 17) //line 1 visible length
{
// print line 1
;
/*
lcd.print(i); //fan[i][0]);
delay(DELAY_LCD/2);
*/
}
else
// set cursor to line 2 once
{
if (!bLine2)
{
lcd.setCursor(0,1);
bLine2++;
}
}
lcd.print(i); //fan[i][0]);
delay(DELAY_LCD/2);
}
BulldogLowell:
HazardsMind:
Set the cursor to display on line 1 and/or line 2, at column 4, and let the code take over.
it appears he is overflowing the available space on the display, no matter how he gets there.
Sir BulldogLowell is right, I need overflow.
Thank you for all the help!
The code is now working
for(int i = 0; i <= 11; i++){
if(fan[i] != 0){
if(i == 0){
dPos=4;
}
else{
if(fan[i-1] < 10){
dPos+=2;
}
else{
dPos+=3;
}
}
if(dLine == 0){
int d;
if(fan[i] < 10){
d=2;
}
else{
d=3;
}
if(dPos+d > 16){
dPos=1;
dLine=1;
}
}
lcd.setCursor(dPos,dLine);
lcd.print(fan[i]);
if(fan[i+1] != 0){
lcd.print(",");
}
else{
lcd.print("?");
}
}
}
I determined if the number of digit the previous number has then I compute if I need to go to the next line by adding the number of digit of the current number.
Please give comments regarding the code
if it works, and you are happy than the code is wonderful!
good to see you worked it out
