Counter output to Tft

Projects Programming
1

I have been working on a counter for reloading project. I finally got the number output on the screen when I press the button, but my problem is when it starts counting it doesn't stop. Here is a copy of my sketch.

#include <TFT.h>

/* Simple Counter

  • ——————
  • This is a simple counter that takes a digital input

*/
const int TftPin = 3; // choose the pin for the TFT input
int switchPin =2; // choose the input pin (for a pushbutton)
int val = 0; // variable for reading the pin status
int counter = 0;
int currentState = 0;
int previousState = 0;

void setup() {
Tft.init();
pinMode(TftPin, OUTPUT); // declare TftPin as output
pinMode(switchPin, INPUT); // declare pushbutton as input
Serial.begin(9600);
}

void loop(){
val = digitalRead(switchPin); // read input value
if (val == HIGH) { // check if the input is HIGH button released)
Tft.drawNumber(counter,75,150,4,BLUE);
currentState = 1;
}
else {
currentState = 0;
}
if(currentState != previousState){
if(currentState == 1){
counter = counter + 1;
delay(500);
Serial.println(counter);
Tft.drawNumber(counter,75,150,4,BLUE);
return;
}
}
previousState = currentState;
delay(600);
}

2 
    if(currentState != previousState)
        {
        if(currentState == 1)
            {
            counter = counter + 1;
            delay(500);
            Serial.println(counter);
            Tft.drawNumber(counter,75,150,4,BLUE);
            return;   //////// This is the mistake.  You leave the function before setting 'previousState'.
            }
       }

    previousState = currentState;
3

I removed the return function, but now it won't count in succession. It just stays at one

4

Note that with all the delay() calls you'll have to release the button for more than a second for the next press to register. Otherwise I can't spot anything obvious. I'd get rid of the delays.

5

Thanks John, it worked fine. Just gotta get everything in the right order for the round counter I'm working on for my reloading press.

Thanks