decimal numbers in arduino serial

Using Arduino Programming Questions
1

Hi
how can I print decimal numbers with decimal point in serial arduino like (1234.23) :cry:
I wroten this sketch but i cant write numbers with decimal point like 342.23

void setup() {
Serial.begin(9600);
Serial.setTimeout(10);

}

void loop() {
char buffer[] = {' ',' ',' ',' ',' ',' ',' ',' ',' '}; // Receive up to 8 bytes
while (!Serial.available()); // Wait for characters
Serial.readBytesUntil('n', buffer, 8);
double incomingValue = atoi(buffer);
Serial.parseFloat();
Serial.print(incomingValue,DEC);
}

please guide me

2

atoi == ASCII to int(eger)

3

May you explain more details?

4

An integer is a whole number - no fractional part.

5

Try running the following line, with n=0,1,2,3,4 and 5.

Serial.println(1.23456,n);
6

Serial.print(incomingValue,DEC); Expecting ten decimal places from a 32 bit float is a bit of an ask.

7

farsad:
Hi
how can I print decimal numbers with decimal point in serial arduino like (1234.23) :cry:
I wroten this sketch but i cant write numbers with decimal point like 342.23

void setup() {

Serial.begin(9600);
Serial.setTimeout(10);
}

void loop() {
char  buffer[] = {' ',' ',' ',' ',' ',' ',' ',' ',' '}; // Receive up to 8 bytes
while (!Serial.available()); // Wait for characters
Serial.readBytesUntil('n', buffer, 8);
double incomingValue = atoi(buffer);
Serial.parseFloat();
Serial.print(incomingValue, DEC);
}




please guide me

Why are you looking for an 'n' in your input?
Why are you doing a .parseFloat() and throwing away the result?
I think what you want is more like:

void loop() {
  while (!Serial.available()); // Wait for characters
  double incomingValue = Serial.parseFloat();
  Serial.print(incomingValue);
}
8

Many thanks to all of you