detachInterupt() from the inside of the interupt function?

Projects General Guidance
6

Arduino 1.8.5 on a 2560 Mega

Yes, you are right. I see that this syntax is valid for the DUE only.

detachInterrupt(1);

Does works with en as well sinse en is just an const int ... But thank you it makes more sense like this.

The code below seems to work well. Volatile interruptFlag seemed to do the trick.
Thank you all very much!

const int en = 3; // Interupt Pin

byte data = 0;
byte cont = 0;

char dArr[100] = {};

int bufLen = 20;//Number of times to call interupt routine
int i = 0;

volatile bool interuptFlag = false; // Indicate if interupt is still activ

//Interupt function on falling enable pin
void enCha()
{
  //Read Ports
  data = PINA;
  cont = PINB;

  if ((cont << 6) == 0b10000000)
  {
    dArr[i] = char(data);
    i++;
    if (i > bufLen)
    {
      interuptFlag = true;
      i = 0;
      detachInterrupt(1);
    }
  }
}

void setup()
{
  Serial.begin(2000000);
}

void loop()
{
  attachInterrupt(digitalPinToInterrupt(en), enCha, FALLING); //Interupt on falling edge
  while (interuptFlag == false) {}; 

  //Print data
  String bufStr(dArr);
  Serial.println(bufStr);

  //Reset
  interuptFlag = false;
}