Display Potentiometer value as percentage

Projects Programming
9

I always use the map function.

and never failed on me, This is the code that I use.

int oldVal;
int TOLERANCE= 5
      int val = analogRead(pot);
      val = map(val, 0, 1023, 0, 100);

      int diff = abs(val - oldVal);

      if (diff > TOLERANCE) )
      {
        Serial.print(val);
        Serial.println("%");
        oldVal = val;// only save if the val has changed enough to avoid slowly drifting
      }

it helped me a lot when I need a certain value that isn't jumping around.

aideax:
int potentiometerValue = analogRead(potentiometerPin);
int percent = map(potentiometerValue , 0, 1023, 0, 100);
Serial.println(percent);

Here's where I got the solution:
https://www.browncountylibrary.org/wp-content/uploads/2018/03/arduino_potentiometer.pdf