Display values from EEPROM to LCD 16x2 display

Using Arduino Storage
1

I'm making a alarm, using ds1307. I want to program the alarm using a lcd shield display, and the problem is that i can print the display but the arduino freezes when I call the function to read the data alarm from the EEPROM.
I'm using like this: addr 0 = hour; addr 1 = minute; addr 2 - 8 days of the week, addr 9 - duration alarm in seconds. So i'm using 10 memorys for each alarm program, my atmega have 1024 bytes, so I can have 102 alarms programs.
I don't understand the reason why arduino freezes. Thanks.

void ler_eeprom() {
//------Read Program Values
{
if (flag_Refresh == 1) { //flag to read just one time
addr = programa * 10; //multiply by 10 to jump to save 10 memories for each program
if (EEPROM.read(addr) > 24)
hour= 0;
else
hour= EEPROM.read(addr); //hour

if ( EEPROM.read(addr + 1) > 59)
minute= 0;
else
minuto = EEPROM.read(addr + 1); //minute

for (int i = 2; addr < 9; i++) {
if (EEPROM.read(addr + i) > 1)
dayOfTheWeek = 1;

  • else*
    _ dayOfTheWeek = EEPROM.read(addr + i);_
    * }*
    * if (EEPROM.read(addr + 9) > 10)*
    * duration_alarm= 3;
    _     else*_
    * duration_alarm= EEPROM.read(addr + 9); //alarm duration*
    * flag_Refresh= 0;
    _     }_
    _     }_
    _    }_
    1_leitura_e2prom.ino (811 Bytes)*
2 
for (int i = 2; addr < 9; i++) {
        if (EEPROM.read(addr + i) > 1)
          dayOfTheWeek = 1;
        else
          dayOfTheWeek = EEPROM.read(addr + i);
      }

How do you expect to exit this for loop when the starting address (addr) is 0?
How do you expect to enter this loop when the starting address(addr) is 10?

I think you want this

for (int i = 2; addr +i < addr +9; i++) {
3

(deleted)

4

Thank you guys, The 'for' loop really was the problem!